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Chapter 5 A Mathematical Model Of Motion Answers

Graphing Motion in One Dimension

    -Position Time Graphs

  • Used to analyze the motion of an object mathematically and to make predictions about its position, velocity, and acceleration

Example question using the graph above:

    1. At what time was the position of the object equal to 40m?

    Answer: 4 seconds

    2. What was the position of the object at 2 seconds?

    Answer: 20m

Graphing the Motion of Two or More Objects

    The two lines (both red and blue) represent students. You can use the information in this position-time graph to determine both students positions.

    Example question:

    At what time do the students cross paths?

   Answer: at approximately 2.2 seconds


Uniform Motion

  • Uniform motion : equal displacements occur during successive equal time intervals
  • A motion diagram and a position-time graph can be used to describe the uniform motion of the plane
  • The slope equation says that the slope of a line is found by determining the amount of rise of the line between any two points divided by the amount of run of the line between the same two points
  • Using the first graph, we can find slope like this:

Graphing Velocity in One Dimension

    -Determining Instantaneous Velocity

    Instantaneous Velocity: velocity at a single point in time (slope of tan line)

    -Velocity-Time Graphs

    Average acceleration: the acceleration of an object between 2 points in time

    Displacement: the linear distance traveled (the area under the curve)

    -If the velocity is constant, the displacement is proportional to the width of the rectangle

    -If you plot the displacement versus time, you will get a straight line with slope equal to velocity

    -If the velocity is increasing, then the area of the rectangle increases in time, so the slope of a displacement-versus-time graph also increases

The shaded area is representative of the displacement during from 0 seconds to 6 seconds.

When you multiply the base and the height, we can see the displacement is 180 m.

    *Area=(6 s) * (30 m/s)

    =180 m

Acceleration

    -Constant acceleration: a constant slope on a velocity-time graph

    -Instantaneous acceleration: the acceleration of an object at an instant of time; the slope of the tangent to the curve on a velocity-time graph

    *found the same way you find the slope of the tangent to the curve on the position-time graph

Positive and Negative Acceleration:

    Positive acceleration is shown by a positive slope, or increasing

    Negative acceleration is shown by a negative slope, or decreasing

Equations of Motion for Uniform Acceleration

Free Fall

    -Acceleration due to gravity: the acceleration of an object in free fall that results from the influence of Earth's gravity

    -ex. You drop a rock. A second later, it's velocity is 9.80 m/s downward. For each second that the rock is falling, its downward velocity increases by 9.80 m/s

Chapter 5 A Mathematical Model Of Motion Answers

Source: https://sites.google.com/site/phunwithphysics7/chapter-5-a-mathematical-model-of-motion

Posted by: jonesfinerstaide.blogspot.com

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